layui form表单提交之后重新加载数据表格的方法

<p style="text-align: center"><img src="https://www.gxlcms.com/Uploads-s/new/2019-09-18-201918/20190911173925.jpg" alt="" /></p>

<div class="layui-row">
 <form class="layui-form layui-col-md12 x-so" id="zq_search">
 菜单：<input id="name" type="text" name="name" placeholder="请输入菜单" autocomplete="off" class="layui-input">
 <button id="search" class="layui-btn" lay-submit="" lay-filter="search"><i class="layui-icon"></i></button>
 </form>
</div>

$(function () {
 //注意：这里是数据表格的加载数据，必须写
 layui.use(['table', 'layer', 'form', 'laypage', 'laydate'], function () {
 var table = layui.table //表格
 ,layer = layui.layer //弹层
 ,form = layui.form //form表单
 // ..................
 
 //监听提交 lay-filter="search"
 form.on('submit(search)', function(data){
 var formData = data.field;
 var name = formData.name,
 url=formData.url,
 icon=formData.icon,
 parent_id=formData.parent_id;
 //执行重载
 table.reload('tableReload', {
 page: {
 curr: 1 //重新从第 1 页开始
 }
 , where: {//这里传参 向后台
 name: name
 //可传多个参数到后台... ，分隔
 }
 , url: '/menu/page'//后台做模糊搜索接口路径
 , method: 'post'
 });
 return false;//false：阻止表单跳转 true：表单跳转
 });
 
 });
});