python中使用urllib2伪造HTTP报头的2个方法

#!/usr/bin/python
# -*- coding: utf-8 -*-
#encoding=utf-8
#Filename:urllib2-header.py
 
import urllib2
import sys
 
#抓取网页内容-发送报头-1
url= "http://www.gxlcms.com"
send_headers = {
 'Host':'www.gxlcms.com',
 'User-Agent':'Mozilla/5.0 (Windows NT 6.2; rv:16.0) Gecko/20100101 Firefox/16.0',
 'Accept':'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8',
 'Connection':'keep-alive'
}
 
req = urllib2.Request(url,headers=send_headers)
r = urllib2.urlopen(req)
 
html = r.read() #返回网页内容
receive_header = r.info() #返回的报头信息
 
# sys.getfilesystemencoding() 
html = html.decode('utf-8','replace').encode(sys.getfilesystemencoding()) #转码:避免

#!/usr/bin/python
# -*- coding: utf-8 -*-
#encoding=utf-8
#Filename:urllib2-header.py
 
import urllib2
import sys
 
url = 'http://www.gxlcms.com'
 
req = urllib2.Request(url)
req.add_header('Referer','http://www.gxlcms.com/')
req.add_header('User-Agent','Mozilla/5.0 (Windows NT 6.2; rv:16.0) Gecko/20100101 Firefox/16.0')
r = urllib2.urlopen(req)
 
html = r.read()
receive_header = r.info()
 
html = html.decode('utf-8').encode(sys.getfilesystemencoding())
 
print receive_header
print '#####################################'
print html