format_num = ["零","壹","贰","叁","肆","伍","陆","柒","捌","玖"]
if type( change_number ) == str:
# - 如果是字符串,先尝试转换成float或int.
if '.' in change_number:
try: change_number = float( change_number )
except: raise ValueError, '%s can\'t change'%change_number
else:
try: change_number = int( change_number )
except: raise ValueError, '%s can\'t change'%change_number
if type( change_number ) == float:
real_numbers = []
for i in range( len( format_word ) - 3, -3, -1 ):
if change_number >= 10 ** i or i < 1:
real_numbers.append( int( round( change_number/( 10**i ), 2)%10 ) )
elif isinstance( change_number, (int, long) ):
real_numbers = [ int( i ) for i in str( change_number ) + '00' ]
else:
raise ValueError, '%s can\'t change'%change_number
zflag = 0 #标记连续0次数,以删除万字,或适时插入零字
start = len(real_numbers) - 3
change_words = []
for i in range(start, -3, -1): #使i对应实际位数,负数为角分
if 0 <> real_numbers[start-i] or len(change_words) == 0:
if zflag:
change_words.append(format_num[0])
zflag = 0
change_words.append( format_num[ real_numbers[ start - i ] ] )
change_words.append(format_word[i+2])
elif 0 == i or (0 == i%4 and zflag < 3): #控制 万/元
change_words.append(format_word[i+2])
zflag = 0
else:
zflag += 1
if change_words[-1] not in ( format_word[0], format_word[1]):
# - 最后两位非"角,分"则补"整"
change_words.append("整")
return ''.join(change_words)
Python 把金额小写转换成大写2
功能将小于十万亿元的小写金额转换为大写
代码如下:
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