Python实现的根据文件名查找数据文件功能示例

#-*- coding: UTF-8 -*-
import os
import shutil
AllFiles=[]
NameFiles=[]
def findFie(filePath):
 pathDir = os.listdir(filePath)
 for allDir in pathDir:
 # print(allDir)
 AllFiles.append(allDir)
 #pass
#filepath = 'C:\Users\IBM_ADMIN\Desktop\cognos\datastage\71&72\71\71sns'
#copyfile = 'C:\Users\IBM_ADMIN\Desktop\cognos\datastage\71&72\71mtp'
filepath = 'C:\Users\IBM_ADMIN\Desktop\cognos\datastage\71&72\72\72sns'
copyfile = 'C:\Users\IBM_ADMIN\Desktop\cognos\datastage\71&72\72mtp'
shutil.rmtree(copyfile)
os.mkdir(copyfile)
findFie(filepath)
def readFile():
 readFile = open('./jobname')
 i = 0
 for eachLine in readFile:
 i= i + 1
 #print(eachLine)
 NameFiles.append(eachLine.replace('
','')) # 去掉换行符
readFile()
#字符串比较
def doTheCompare():
 for x in NameFiles:
 print(x)
 for y in AllFiles:
 if x == y :
 copyFrom = os.path.join(filepath,x)
 copyTo = os.path.join(copyfile,x)
 shutil.copyfile(copyFrom,copyTo)
 else:
 pass
 #print ("file not find under sns process,thanks .please check with wumi.")
doTheCompare()

# -*- coding:utf-8 -*-
import os
def search(path=".", name="1"):
 for item in os.listdir(path):
 item_path = os.path.join(path, item)
 if os.path.isdir(item_path):
 search(item_path, name)
 elif os.path.isfile(item_path):
 if name in item:
 print(item_path)
if __name__ == "__main__":
 search(path=r"D:360Downloads",name="dll")